Work done = force × distance moved in the direction of the force. is done when energy is transferred from one store to another. Work is also done when a force causes an object to move. The easiest way to calculate gravitational potential energy is to use our potential energy calculator. This tool estimates the potential energy on the basis of three values. These are: The mass of the object; Gravitational acceleration, which on Earth amounts to. 9.81 m / s 2. 9.81 \ \mathrm {m/s^2} 9.81 m/s2 or. 1 g. See Answer. W app = (10 N) * (5 m) * cos (0 deg) = +50 Joules. W frict = (10 N) * (5 m) * cos (180 deg) = -50 Joules. An approximately 2-kg object is sliding at constant speed across a friction free surface for a displacement of 5 m to the right. See Answer. Neither of these forces do work. The acceleration of both blocks is the same and is equal to (M 2 g)/ (M 1 +M 2 ), or 4.86 m/s 2. The work done on each block is equal to their final kinetic energy and added together equals 40.71 J, which is the total work done on the system. Yes I'd say this is a satisfactory understanding. Calculate the work done, if a wire is loaded by 'Mg' weight and the increase in length is 'l' What is percentage increase in the length of a wire of diameter 2.5 mm stretched by a force of 100 kg weight? youngs modulus of elasticity of wire is 12.5 * 10 to power 11 dyne / cm square Question 4: Calculate the work done when: (i) A 5 kg weight is lifted 10 m vertically upward (g = 9.8 ms-2). (ii) A car is moved on a rough road through 3 m against a frictional resistance of 75 N. Solution: Question 5: An electric motor of power 100 W is used to drive the stirrer in a water bath. If 50% of the energy supplied to the motor is Example 11.2 A porter lifts a luggage of 15 kg from the ground and puts it on his head 1.5 m above the ground. Calculate the work done by him on the luggage.Mass of luggage = 15 kgHeight of luggage = h = 1.5 mWork done = Force × DistanceForce = Weight of luggage= m × g∴ Work done = A block of mass m= 3:20 kg is pushed a distance d = 4.60 m along a frictionless, horizontal table by a constant applied force of magnitude F = 16.0 N directed at an angle = 26.0 below the horizontal as shown in the gure below. a) Determine the work done on the block by the applied force. b) Determine the work done on the block by the normal force Momentum, Impulse, and the Impulse-Momentum Theorem. Linear momentum is the product of a system's mass and its velocity. In equation form, linear momentum p is. p = mv. p = m v. You can see from the equation that momentum is directly proportional to the object's mass ( m) and velocity ( v ). Therefore, the greater an object's mass or the Calculus questions and answers. 1. Use correct units! a) Calculate the amount of work done if a 418 lb. rat is lifted 10 feet off the ground. b) Convert weight to kilograms, distance to meters. (hundredths) c) Calculate work done, metric version. I foot = 0.305 meters 2.2 pounds = 1 kg (nearest unit) i) 418 lbs. = kg ii) 10 ft. = meters 2. vw8MT.